Constructive quantum field theory — Lecture 6 (slides)

Why not Polchinski with a frozen cube?

Programme: keep \(- \frac{\lambda}{3} \varphi^3\) unclipped, clip the higher orders (result: \(f\)), pay in the source of \(R = F - f\). Test it on one site: \(K_q = q\), \(S = 1 / q\).

\(\displaystyle F_q (x) = - \frac{\lambda}{3} \mathbb{E}_x \Phi_{\infty}^3 = q (m_q (x) - x), \quad |m_q (x) | \leqslant 2 (\lambda / 3)^{- 1 / 4} + 2 (3 q|x| / \lambda)^{1 / 3} .\)
Figure from Constructive quantum field theory — Lecture 6 (slides)

So \(3 R / (\lambda x^3) \to 1\): the remainder cancels the cube (the dip: \(R\) changes sign, Wick term below, cube above). Field equation: \(qx = (q - q_0) m_q + \omega_q\), only linear confinement.